What are the solutions to the equation n^2+12n+108=12 ?

The solutions to the equation n^2+12n+108=12 are n=-6+2sqrt(15)i,n=-6-2sqrt(15)i

Find the zeros of n^2+12n+108=12

The zeros of n^2+12n+108=12 are n=-6+2sqrt(15)i,n=-6-2sqrt(15)i

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n^{2} + 12 n + 108 = 12

n = - 6 + 215 i, n = - 6 - 215 i

Solution steps

n^{2} + 12 n + 108 = 12

Move

12

to the left side

n^{2} + 12 n + 96 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 96}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 96 : 415 i

n_{1, 2} = \frac{- 12 \pm 4 15 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 12 + 4 15 i}{2 \cdot 1}, n_{2} = \frac{- 12 - 4 15 i}{2 \cdot 1}

n = \frac{- 12 + 4 15 i}{2 \cdot 1} : - 6 + 215 i

n = \frac{- 12 - 4 15 i}{2 \cdot 1} : - 6 - 215 i

The solutions to the quadratic equation are:

n = - 6 + 215 i, n = - 6 - 215 i

- (1 - t)^{2} = - 25

x^{2} + 3^{2} = 9^{2}

4.96 \cdot 1 0^{- 10} = 6.4 \cdot 1 0^{- 9} \cdot x^{2}

2 x^{2} + 6 x + \frac{1}{2} = 0

x, 19 x^{2} + 243 x y - 5 y^{2} - 527 = 0

What are the solutions to the equation n^2+12n+108=12 ?
The solutions to the equation n^2+12n+108=12 are n=-6+2sqrt(15)i,n=-6-2sqrt(15)i
Find the zeros of n^2+12n+108=12
The zeros of n^2+12n+108=12 are n=-6+2sqrt(15)i,n=-6-2sqrt(15)i