What are the solutions to the equation 6p^2-4p-5=0 ?

The solutions to the equation 6p^2-4p-5=0 are p=(2+sqrt(34))/6 ,p=(2-sqrt(34))/6

Find the zeros of 6p^2-4p-5=0

The zeros of 6p^2-4p-5=0 are p=(2+sqrt(34))/6 ,p=(2-sqrt(34))/6

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6 p^{2} - 4 p - 5 = 0

p = \frac{2 + 34}{6}, p = \frac{2 - 34}{6}

Decimal Notation

p = 1.30515 \dots, p = - 0.63849 \dots

Solution steps

6 p^{2} - 4 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 4)^{2} - 4 \cdot 6 (- 5) = 234

p_{1, 2} = \frac{- ( - 4 ) \pm 2 34}{2 \cdot 6}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 2 34}{2 \cdot 6}, p_{2} = \frac{- ( - 4 ) - 2 34}{2 \cdot 6}

p = \frac{- ( - 4 ) + 2 34}{2 \cdot 6} : \frac{2 + 34}{6}

p = \frac{- ( - 4 ) - 2 34}{2 \cdot 6} : \frac{2 - 34}{6}

The solutions to the quadratic equation are:

p = \frac{2 + 34}{6}, p = \frac{2 - 34}{6}

(4 x - 7)^{2} + 13 = - 11

- x^{2} + 22 x + 112 = 0

x^{2} + 9 x - 360 = 0

2 g^{2} - 6 g - 9 = 0

(2 k - 1)^{2} = - 27

What are the solutions to the equation 6p^2-4p-5=0 ?
The solutions to the equation 6p^2-4p-5=0 are p=(2+sqrt(34))/6 ,p=(2-sqrt(34))/6
Find the zeros of 6p^2-4p-5=0
The zeros of 6p^2-4p-5=0 are p=(2+sqrt(34))/6 ,p=(2-sqrt(34))/6