What are the solutions to the equation 20x^2-21x+4=0 ?

The solutions to the equation 20x^2-21x+4=0 are x= 4/5 ,x= 1/4

Find the zeros of 20x^2-21x+4=0

The zeros of 20x^2-21x+4=0 are x= 4/5 ,x= 1/4

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20 x^{2} - 21 x + 4 = 0

x = \frac{4}{5}, x = \frac{1}{4}

Decimal Notation

x = 0.8, x = 0.25

Solution steps

20 x^{2} - 21 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 20 \cdot 4}{2 \cdot 20}

(- 21)^{2} - 4 \cdot 20 \cdot 4 = 11

x_{1, 2} = \frac{- ( - 21 ) \pm 11}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 11}{2 \cdot 20}, x_{2} = \frac{- ( - 21 ) - 11}{2 \cdot 20}

x = \frac{- ( - 21 ) + 11}{2 \cdot 20} : \frac{4}{5}

x = \frac{- ( - 21 ) - 11}{2 \cdot 20} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = \frac{1}{4}

13^{2} + b^{2} = 77^{2}

3 x + 8 = 2 x^{2}

- 7 x^{2} - 8 x + 7 = 0

p^{2} - 20 p

(x) (x - 6) = 135

What are the solutions to the equation 20x^2-21x+4=0 ?
The solutions to the equation 20x^2-21x+4=0 are x= 4/5 ,x= 1/4
Find the zeros of 20x^2-21x+4=0
The zeros of 20x^2-21x+4=0 are x= 4/5 ,x= 1/4