What are the solutions to the equation -7x^2-8x+7=0 ?

The solutions to the equation -7x^2-8x+7=0 are x=-(4+sqrt(65))/7 ,x=(sqrt(65)-4)/7

Find the zeros of -7x^2-8x+7=0

The zeros of -7x^2-8x+7=0 are x=-(4+sqrt(65))/7 ,x=(sqrt(65)-4)/7

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- 7 x^{2} - 8 x + 7 = 0

x = - \frac{4 + 65}{7}, x = \frac{65 - 4}{7}

Decimal Notation

x = - 1.72317 \dots, x = 0.58032 \dots

Solution steps

- 7 x^{2} - 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 7 ) \cdot 7}{2 ( - 7 )}

(- 8)^{2} - 4 (- 7) \cdot 7 = 265

x_{1, 2} = \frac{- ( - 8 ) \pm 2 65}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 65}{2 ( - 7 )}, x_{2} = \frac{- ( - 8 ) - 2 65}{2 ( - 7 )}

x = \frac{- ( - 8 ) + 2 65}{2 ( - 7 )} : - \frac{4 + 65}{7}

x = \frac{- ( - 8 ) - 2 65}{2 ( - 7 )} : \frac{65 - 4}{7}

The solutions to the quadratic equation are:

x = - \frac{4 + 65}{7}, x = \frac{65 - 4}{7}

p^{2} - 20 p

(x) (x - 6) = 135

9 y^{2} + 21 y - 18 = 0

16 x^{2} + 32 x

15 + 2 y = y^{2}

What are the solutions to the equation -7x^2-8x+7=0 ?
The solutions to the equation -7x^2-8x+7=0 are x=-(4+sqrt(65))/7 ,x=(sqrt(65)-4)/7
Find the zeros of -7x^2-8x+7=0
The zeros of -7x^2-8x+7=0 are x=-(4+sqrt(65))/7 ,x=(sqrt(65)-4)/7