What are the solutions to the equation x^2+16x-4=0 ?

The solutions to the equation x^2+16x-4=0 are x=2(sqrt(17)-4),x=-2(4+sqrt(17))

Find the zeros of x^2+16x-4=0

The zeros of x^2+16x-4=0 are x=2(sqrt(17)-4),x=-2(4+sqrt(17))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 16 x - 4 = 0

x = 2 (17 - 4), x = - 2 (4 + 17)

Decimal Notation

x = 0.24621 \dots, x = - 16.24621 \dots

Solution steps

x^{2} + 16 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 4) = 417

x_{1, 2} = \frac{- 16 \pm 4 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 17}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 17}{2 \cdot 1}

x = \frac{- 16 + 4 17}{2 \cdot 1} : 2 (17 - 4)

x = \frac{- 16 - 4 17}{2 \cdot 1} : - 2 (4 + 17)

The solutions to the quadratic equation are:

x = 2 (17 - 4), x = - 2 (4 + 17)

9 x^{2} - 12 x + 3 = 0

3 y^{2} + 4 y = 15

t^{2} - 3 t - 10 = 0

x^{2} + 8 x + 12 = 0

2 x^{2} + 28 x + 82 = 0

What are the solutions to the equation x^2+16x-4=0 ?
The solutions to the equation x^2+16x-4=0 are x=2(sqrt(17)-4),x=-2(4+sqrt(17))
Find the zeros of x^2+16x-4=0
The zeros of x^2+16x-4=0 are x=2(sqrt(17)-4),x=-2(4+sqrt(17))