What are the solutions to the equation 2y^2=-8 ?

The solutions to the equation 2y^2=-8 are y=2i,y=-2i

Find the zeros of 2y^2=-8

The zeros of 2y^2=-8 are y=2i,y=-2i

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2 y^{2} = - 8

y = 2 i, y = - 2 i

Solution steps

2 y^{2} = - 8

Divide both sides by

2

y^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4, y = - - 4

- 4 = 2 i

- - 4 = - 2 i

y = 2 i, y = - 2 i

- 6 y^{2} + 5 y + 2 = 0

9 x^{2} - 3 x + 4 = 0

x^{2} - 1.2 x + 0.2 = 0

x, 5 x^{2} - 7 x = 1

x^{(2)} - x - 2 = 0

What are the solutions to the equation 2y^2=-8 ?
The solutions to the equation 2y^2=-8 are y=2i,y=-2i
Find the zeros of 2y^2=-8
The zeros of 2y^2=-8 are y=2i,y=-2i