What are the solutions to the equation 25x^2+36=0 ?

The solutions to the equation 25x^2+36=0 are x= 6/5 i,x=-6/5 i

Find the zeros of 25x^2+36=0

The zeros of 25x^2+36=0 are x= 6/5 i,x=-6/5 i

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25 x^{2} + 36 = 0

x = \frac{6}{5} i, x = - \frac{6}{5} i

Solution steps

25 x^{2} + 36 = 0

Move

36

to the right side

25 x^{2} = - 36

Divide both sides by

25

x^{2} = - \frac{36}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{36}{25}, x = - - \frac{36}{25}

- \frac{36}{25} = \frac{6}{5} i

- - \frac{36}{25} = - \frac{6}{5} i

x = \frac{6}{5} i, x = - \frac{6}{5} i

n^{2} - 8 n - 20 = 0

5 (- 1)^{2} = x (- 1)^{3} - 1 + x^{2}

4 x^{2} - 6 x - 2 = 0

2 x^{2} - 4 x + 4 = 2

x, x^{2} + x + 6 = 0

What are the solutions to the equation 25x^2+36=0 ?
The solutions to the equation 25x^2+36=0 are x= 6/5 i,x=-6/5 i
Find the zeros of 25x^2+36=0
The zeros of 25x^2+36=0 are x= 6/5 i,x=-6/5 i