What are the solutions to the equation solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2 ?

The solutions to the equation solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2 are x=0

Find the zeros of solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2

The zeros of solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2 are x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, (x^{2} + 2 y) (x^{2} - 3 y) = x^{4} - 6 y^{2}

x = 0

Solution steps

(x^{2} + 2 y) (x^{2} - 3 y) = x^{4} - 6 y^{2}

Expand

(x^{2} + 2 y) (x^{2} - 3 y) : x^{4} - x^{2} y - 6 y^{2}

x^{4} - x^{2} y - 6 y^{2} = x^{4} - 6 y^{2}

Move

6 y^{2}

to the right side

x^{4} - x^{2} y = x^{4}

Move

x^{4}

to the left side

- x^{2} y = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

x = 0

3 x^{2} + 7 x

x, x^{2} + 4 x y - 3 y^{2} + x + 2 y - 6 = 0

\frac{k ^{2}}{1.2} - 7 = 23

8 x - 65 = x^{2}

t^{2} + 26 t

What are the solutions to the equation solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2 ?
The solutions to the equation solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2 are x=0
Find the zeros of solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2
The zeros of solvefor x,(x^2+2y)(x^2-3y)=x^4-6y^2 are x=0