What are the solutions to the equation completesquare 3x^2+7x ?

The solutions to the equation completesquare 3x^2+7x are 3(x+7/6)^2-49/12

Find the zeros of completesquare 3x^2+7x

The zeros of completesquare 3x^2+7x are 3(x+7/6)^2-49/12

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complete the square

3 x^{2} + 7 x

3 (x + \frac{7}{6})^{2} - \frac{49}{12}

Solution steps

3 x^{2} + 7 x

Write

3 x^{2} + 7 x

in the form:

x^{2} + 2 a x + a^{2}

Factor out

3

3 (x^{2} + \frac{7 x}{3})

2 a = \frac{7}{3} : a = \frac{7}{6}

Add and subtract

(\frac{7}{6})^{2}

3 (x^{2} + \frac{7 x}{3} + (\frac{7}{6})^{2} - (\frac{7}{6})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + \frac{7}{3} x + (\frac{7}{6})^{2} = (x + \frac{7}{6})^{2}

3 ((x + \frac{7}{6})^{2} - (\frac{7}{6})^{2})

Simplify

3 (x + \frac{7}{6})^{2} - \frac{49}{12}

x, x^{2} + 4 x y - 3 y^{2} + x + 2 y - 6 = 0

\frac{k ^{2}}{1.2} - 7 = 23

8 x - 65 = x^{2}

t^{2} + 26 t

8 x^{2} + 33 x + 4 = 0

What are the solutions to the equation completesquare 3x^2+7x ?
The solutions to the equation completesquare 3x^2+7x are 3(x+7/6)^2-49/12
Find the zeros of completesquare 3x^2+7x
The zeros of completesquare 3x^2+7x are 3(x+7/6)^2-49/12