What are the solutions to the equation 20x^2+8x+4=0 ?

The solutions to the equation 20x^2+8x+4=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5

Find the zeros of 20x^2+8x+4=0

The zeros of 20x^2+8x+4=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5

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20 x^{2} + 8 x + 4 = 0

x = - \frac{1}{5} + i \frac{2}{5}, x = - \frac{1}{5} - i \frac{2}{5}

Solution steps

20 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 20 \cdot 4}{2 \cdot 20}

Simplify

8^{2} - 4 \cdot 20 \cdot 4 : 16 i

x_{1, 2} = \frac{- 8 \pm 16 i}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 8 + 16 i}{2 \cdot 20}, x_{2} = \frac{- 8 - 16 i}{2 \cdot 20}

x = \frac{- 8 + 16 i}{2 \cdot 20} : - \frac{1}{5} + i \frac{2}{5}

x = \frac{- 8 - 16 i}{2 \cdot 20} : - \frac{1}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{2}{5}, x = - \frac{1}{5} - i \frac{2}{5}

- 8 y + 3 y^{2} + 4 = 0

(3 - x) (- 2 - x) + 6 = 0

7 x^{2} + 4 x + 2 = 0

6 r^{2} - 4 r - 80 = 0

12 x^{2} - 128 x + 252 = 0

What are the solutions to the equation 20x^2+8x+4=0 ?
The solutions to the equation 20x^2+8x+4=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5
Find the zeros of 20x^2+8x+4=0
The zeros of 20x^2+8x+4=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5