What are the solutions to the equation 0=x^2+7x+12 ?

The solutions to the equation 0=x^2+7x+12 are x=-3,x=-4

Find the zeros of 0=x^2+7x+12

The zeros of 0=x^2+7x+12 are x=-3,x=-4

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0 = x^{2} + 7 x + 12

x = - 3, x = - 4

Solution steps

0 = x^{2} + 7 x + 12

Switch sides

x^{2} + 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 1}, x_{2} = \frac{- 7 - 1}{2 \cdot 1}

x = \frac{- 7 + 1}{2 \cdot 1} : - 3

x = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

8 c^{2} - 3 = 93

95 x^{2} + 56 x + 6719 = 0

q^{2} + 40 q = 0

x = 5 x (1 - x)

3 z^{2} - 4 z + 5 = 0

What are the solutions to the equation 0=x^2+7x+12 ?
The solutions to the equation 0=x^2+7x+12 are x=-3,x=-4
Find the zeros of 0=x^2+7x+12
The zeros of 0=x^2+7x+12 are x=-3,x=-4