What are the solutions to the equation m^2+18m+75=-2 ?

The solutions to the equation m^2+18m+75=-2 are m=-7,m=-11

Find the zeros of m^2+18m+75=-2

The zeros of m^2+18m+75=-2 are m=-7,m=-11

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m^{2} + 18 m + 75 = - 2

m = - 7, m = - 11

Solution steps

m^{2} + 18 m + 75 = - 2

Move

2

to the left side

m^{2} + 18 m + 77 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 77}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 77 = 4

m_{1, 2} = \frac{- 18 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 18 + 4}{2 \cdot 1}, m_{2} = \frac{- 18 - 4}{2 \cdot 1}

m = \frac{- 18 + 4}{2 \cdot 1} : - 7

m = \frac{- 18 - 4}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

m = - 7, m = - 11

(2 - x) (2 - x) = 0

- x^{2} - x - 3 = 0

p^{2} - 5 = 4

x^{2} + 10 x + 12 = 0

12 (- 2 k - 4)^{2} - 1 (- 2 k - 4) - 6 = 0

What are the solutions to the equation m^2+18m+75=-2 ?
The solutions to the equation m^2+18m+75=-2 are m=-7,m=-11
Find the zeros of m^2+18m+75=-2
The zeros of m^2+18m+75=-2 are m=-7,m=-11