What are the solutions to the equation e^2+7e-60=0 ?

The solutions to the equation e^2+7e-60=0 are e=5,e=-12

Find the zeros of e^2+7e-60=0

The zeros of e^2+7e-60=0 are e=5,e=-12

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e^{2} + 7 e - 60 = 0

e = 5, e = - 12

Solution steps

e^{2} + 7 e - 60 = 0

Solve with the quadratic formula

e_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 60) = 17

e_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 1}

Separate the solutions

e_{1} = \frac{- 7 + 17}{2 \cdot 1}, e_{2} = \frac{- 7 - 17}{2 \cdot 1}

e = \frac{- 7 + 17}{2 \cdot 1} : 5

e = \frac{- 7 - 17}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

e = 5, e = - 12

5 - 25 x = - 8 x^{2} + 2

- 6 x^{2} + 78 x - 240 = 0

3 p^{2} - 14 p = 5

3 x^{2} + 11 x = 0

- \frac{1}{2} x^{2} + x + 4 = 0

What are the solutions to the equation e^2+7e-60=0 ?
The solutions to the equation e^2+7e-60=0 are e=5,e=-12
Find the zeros of e^2+7e-60=0
The zeros of e^2+7e-60=0 are e=5,e=-12