What are the solutions to the equation m^2-9m+14=0 ?

The solutions to the equation m^2-9m+14=0 are m=7,m=2

Find the zeros of m^2-9m+14=0

The zeros of m^2-9m+14=0 are m=7,m=2

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m^{2} - 9 m + 14 = 0

m = 7, m = 2

Solution steps

m^{2} - 9 m + 14 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

m_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, m_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

m = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

m = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

m = 7, m = 2

m^{2} - 2 m - 16 = 0

x^{2} - 4 x - 7 = 0

x^{2} + 10 x + 23 = 0

x, z = 2 x + 4 y - x^{2} - y^{2} - 3

x^{2} + 4 x = 95

What are the solutions to the equation m^2-9m+14=0 ?
The solutions to the equation m^2-9m+14=0 are m=7,m=2
Find the zeros of m^2-9m+14=0
The zeros of m^2-9m+14=0 are m=7,m=2