What are the solutions to the equation solvefor y,x=(y-3)^2 ?

The solutions to the equation solvefor y,x=(y-3)^2 are y=sqrt(x)+3,y=-sqrt(x)+3

Find the zeros of solvefor y,x=(y-3)^2

The zeros of solvefor y,x=(y-3)^2 are y=sqrt(x)+3,y=-sqrt(x)+3

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solve for

y, x = (y - 3)^{2}

y = x + 3, y = - x + 3

Solution steps

x = (y - 3)^{2}

Switch sides

(y - 3)^{2} = x

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 3 = x : y = x + 3

Solve

y - 3 = - x : y = - x + 3

The solutions to the quadratic equation are:

y = x + 3, y = - x + 3

2.1 x^{2} - 4.7 x - 6.2 = 0

x^{2} + (- 3 x + 5)^{2} = 25

- 5 x^{2} + 9 x - 8 = - 8

12 x^{2} + 10 x + 1 = 0

170 = t^{2} + 13 t + 130

What are the solutions to the equation solvefor y,x=(y-3)^2 ?
The solutions to the equation solvefor y,x=(y-3)^2 are y=sqrt(x)+3,y=-sqrt(x)+3
Find the zeros of solvefor y,x=(y-3)^2
The zeros of solvefor y,x=(y-3)^2 are y=sqrt(x)+3,y=-sqrt(x)+3