What are the solutions to the equation x^2+(-3x+5)^2=25 ?

The solutions to the equation x^2+(-3x+5)^2=25 are x=3,x=0

Find the zeros of x^2+(-3x+5)^2=25

The zeros of x^2+(-3x+5)^2=25 are x=3,x=0

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x^{2} + (- 3 x + 5)^{2} = 25

x = 3, x = 0

Solution steps

x^{2} + (- 3 x + 5)^{2} = 25

Expand

x^{2} + (- 3 x + 5)^{2} : 10 x^{2} - 30 x + 25

10 x^{2} - 30 x + 25 = 25

Move

25

to the left side

10 x^{2} - 30 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 10 \cdot 0}{2 \cdot 10}

(- 30)^{2} - 4 \cdot 10 \cdot 0 = 30

x_{1, 2} = \frac{- ( - 30 ) \pm 30}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 30}{2 \cdot 10}, x_{2} = \frac{- ( - 30 ) - 30}{2 \cdot 10}

x = \frac{- ( - 30 ) + 30}{2 \cdot 10} : 3

x = \frac{- ( - 30 ) - 30}{2 \cdot 10} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

- 5 x^{2} + 9 x - 8 = - 8

12 x^{2} + 10 x + 1 = 0

170 = t^{2} + 13 t + 130

6 - 6 x^{2} = 0

16 - 5 x^{2} = - 21 x^{2} + 25

What are the solutions to the equation x^2+(-3x+5)^2=25 ?
The solutions to the equation x^2+(-3x+5)^2=25 are x=3,x=0
Find the zeros of x^2+(-3x+5)^2=25
The zeros of x^2+(-3x+5)^2=25 are x=3,x=0