What are the solutions to the equation p^2-8p+15=0 ?

The solutions to the equation p^2-8p+15=0 are p=5,p=3

Find the zeros of p^2-8p+15=0

The zeros of p^2-8p+15=0 are p=5,p=3

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p^{2} - 8 p + 15 = 0

p = 5, p = 3

Solution steps

p^{2} - 8 p + 15 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

p_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, p_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

p = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

p = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

p = 5, p = 3

2 x^{2} + 10 x + 9 = 0

12 x^{2} - 48 x + 39 = 0

4 - x^{2} = - x

4 q^{2} + 9 q + 4 = 0

s^{2} + 2 s + 13 = 0

What are the solutions to the equation p^2-8p+15=0 ?
The solutions to the equation p^2-8p+15=0 are p=5,p=3
Find the zeros of p^2-8p+15=0
The zeros of p^2-8p+15=0 are p=5,p=3