What are the solutions to the equation 6t^2+14=-25t ?

The solutions to the equation 6t^2+14=-25t are t=-2/3 ,t=-7/2

Find the zeros of 6t^2+14=-25t

The zeros of 6t^2+14=-25t are t=-2/3 ,t=-7/2

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6 t^{2} + 14 = - 25 t

t = - \frac{2}{3}, t = - \frac{7}{2}

Decimal Notation

t = - 0.66666 \dots, t = - 3.5

Solution steps

6 t^{2} + 14 = - 25 t

Move

25 t

to the left side

6 t^{2} + 14 + 25 t = 0

Write in the standard form

a x^{2} + b x + c = 0

6 t^{2} + 25 t + 14 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 6 \cdot 14}{2 \cdot 6}

2 5^{2} - 4 \cdot 6 \cdot 14 = 17

t_{1, 2} = \frac{- 25 \pm 17}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- 25 + 17}{2 \cdot 6}, t_{2} = \frac{- 25 - 17}{2 \cdot 6}

t = \frac{- 25 + 17}{2 \cdot 6} : - \frac{2}{3}

t = \frac{- 25 - 17}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

t = - \frac{2}{3}, t = - \frac{7}{2}

4 x^{2} + 15 x + 9 = 0

0 = 4800 - \frac{3}{4} x^{2}

5 x^{2} - 12 x = - 3

(2 x - 1) (x + 4) = 8 x + 2

8^{2} + 2^{2} = c^{2}

What are the solutions to the equation 6t^2+14=-25t ?
The solutions to the equation 6t^2+14=-25t are t=-2/3 ,t=-7/2
Find the zeros of 6t^2+14=-25t
The zeros of 6t^2+14=-25t are t=-2/3 ,t=-7/2