What are the solutions to the equation 12x^2+13x-35=0 ?

The solutions to the equation 12x^2+13x-35=0 are x= 5/4 ,x=-7/3

Find the zeros of 12x^2+13x-35=0

The zeros of 12x^2+13x-35=0 are x= 5/4 ,x=-7/3

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12 x^{2} + 13 x - 35 = 0

x = \frac{5}{4}, x = - \frac{7}{3}

Decimal Notation

x = 1.25, x = - 2.33333 \dots

Solution steps

12 x^{2} + 13 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 12 ( - 35 )}{2 \cdot 12}

1 3^{2} - 4 \cdot 12 (- 35) = 43

x_{1, 2} = \frac{- 13 \pm 43}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 13 + 43}{2 \cdot 12}, x_{2} = \frac{- 13 - 43}{2 \cdot 12}

x = \frac{- 13 + 43}{2 \cdot 12} : \frac{5}{4}

x = \frac{- 13 - 43}{2 \cdot 12} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{7}{3}

a^{2} = - 1, 0 y (a) a^{10} = 24

0 = 3 x^{2} - 10 x + 4

3 x^{2} - 36 = 3 x

x, (x + 2)^{2} + (y + 1)^{2} = 0

(z - 4)^{2} = (3 - z) (1 + 2 z)

What are the solutions to the equation 12x^2+13x-35=0 ?
The solutions to the equation 12x^2+13x-35=0 are x= 5/4 ,x=-7/3
Find the zeros of 12x^2+13x-35=0
The zeros of 12x^2+13x-35=0 are x= 5/4 ,x=-7/3