What are the solutions to the equation 0=-16t^2+96t+4 ?

The solutions to the equation 0=-16t^2+96t+4 are t=-(-6+sqrt(37))/2 ,t=(6+sqrt(37))/2

Find the zeros of 0=-16t^2+96t+4

The zeros of 0=-16t^2+96t+4 are t=-(-6+sqrt(37))/2 ,t=(6+sqrt(37))/2

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0 = - 16 t^{2} + 96 t + 4

t = - \frac{- 6 + 37}{2}, t = \frac{6 + 37}{2}

Decimal Notation

t = - 0.04138 \dots, t = 6.04138 \dots

Solution steps

0 = - 16 t^{2} + 96 t + 4

Switch sides

- 16 t^{2} + 96 t + 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 4}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 4 = 1637

t_{1, 2} = \frac{- 96 \pm 16 37}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 16 37}{2 ( - 16 )}, t_{2} = \frac{- 96 - 16 37}{2 ( - 16 )}

t = \frac{- 96 + 16 37}{2 ( - 16 )} : - \frac{- 6 + 37}{2}

t = \frac{- 96 - 16 37}{2 ( - 16 )} : \frac{6 + 37}{2}

The solutions to the quadratic equation are:

t = - \frac{- 6 + 37}{2}, t = \frac{6 + 37}{2}

1 0^{2} + b^{2} = 2 0^{2}

36 u = 9 u^{2}

3 x^{2} = 5 x - 3

- x^{2} - 12 = 0

4^{2} + 1 2^{2} = x^{2}

What are the solutions to the equation 0=-16t^2+96t+4 ?
The solutions to the equation 0=-16t^2+96t+4 are t=-(-6+sqrt(37))/2 ,t=(6+sqrt(37))/2
Find the zeros of 0=-16t^2+96t+4
The zeros of 0=-16t^2+96t+4 are t=-(-6+sqrt(37))/2 ,t=(6+sqrt(37))/2