What are the solutions to the equation -2x^2+2x+9=-5x ?

The solutions to the equation -2x^2+2x+9=-5x are x=-1,x= 9/2

Find the zeros of -2x^2+2x+9=-5x

The zeros of -2x^2+2x+9=-5x are x=-1,x= 9/2

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- 2 x^{2} + 2 x + 9 = - 5 x

x = - 1, x = \frac{9}{2}

Decimal Notation

x = - 1, x = 4.5

Solution steps

- 2 x^{2} + 2 x + 9 = - 5 x

Move

5 x

to the left side

- 2 x^{2} + 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) \cdot 9}{2 ( - 2 )}

7^{2} - 4 (- 2) \cdot 9 = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 ( - 2 )}, x_{2} = \frac{- 7 - 11}{2 ( - 2 )}

x = \frac{- 7 + 11}{2 ( - 2 )} : - 1

x = \frac{- 7 - 11}{2 ( - 2 )} : \frac{9}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{9}{2}

p, \frac{3 p ^{2} - x}{y} = \frac{- x + 17}{- 4}

x^{2} + (7 - x)^{2} = 49

- 3 (x + 2)^{2} = 12

x^{2} = 7 x + 12

x^{2} + 5 x = - 6

What are the solutions to the equation -2x^2+2x+9=-5x ?
The solutions to the equation -2x^2+2x+9=-5x are x=-1,x= 9/2
Find the zeros of -2x^2+2x+9=-5x
The zeros of -2x^2+2x+9=-5x are x=-1,x= 9/2