What are the solutions to the equation x^2+(7-x)^2=49 ?

The solutions to the equation x^2+(7-x)^2=49 are x=7,x=0

Find the zeros of x^2+(7-x)^2=49

The zeros of x^2+(7-x)^2=49 are x=7,x=0

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x^{2} + (7 - x)^{2} = 49

x = 7, x = 0

Solution steps

x^{2} + (7 - x)^{2} = 49

Expand

x^{2} + (7 - x)^{2} : 2 x^{2} - 14 x + 49

2 x^{2} - 14 x + 49 = 49

Move

49

to the left side

2 x^{2} - 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 0 = 14

x_{1, 2} = \frac{- ( - 14 ) \pm 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 14}{2 \cdot 2}

x = \frac{- ( - 14 ) + 14}{2 \cdot 2} : 7

x = \frac{- ( - 14 ) - 14}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

- 3 (x + 2)^{2} = 12

x^{2} = 7 x + 12

x^{2} + 5 x = - 6

r, x^{2} - y^{2} = r^{2}

x^{2} - 15 x = - 26

What are the solutions to the equation x^2+(7-x)^2=49 ?
The solutions to the equation x^2+(7-x)^2=49 are x=7,x=0
Find the zeros of x^2+(7-x)^2=49
The zeros of x^2+(7-x)^2=49 are x=7,x=0