What are the solutions to the equation (x)=x^2+x-6 ?

The solutions to the equation (x)=x^2+x-6 are x=sqrt(6),x=-sqrt(6)

Find the zeros of (x)=x^2+x-6

The zeros of (x)=x^2+x-6 are x=sqrt(6),x=-sqrt(6)

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(x) = x^{2} + x - 6

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

(x) = x^{2} + x - 6

Refine

x = x^{2} + x - 6

Switch sides

x^{2} + x - 6 = x

Move

6

to the right side

x^{2} + x = x + 6

Move

x

to the left side

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

x^{2} + 3 x + 2 = x + 2

- 2 x^{2} + 12 x - 13 = 0

2 x^{2} - 6 x + \frac{9}{2} = 0

(3 x - 1)^{2} = x^{2} + 21

x^{2} = - x^{2} + 2 x + 4

What are the solutions to the equation (x)=x^2+x-6 ?
The solutions to the equation (x)=x^2+x-6 are x=sqrt(6),x=-sqrt(6)
Find the zeros of (x)=x^2+x-6
The zeros of (x)=x^2+x-6 are x=sqrt(6),x=-sqrt(6)