What are the solutions to the equation 6x^2+19x+4=2x-1 ?

The solutions to the equation 6x^2+19x+4=2x-1 are x=-1/3 ,x=-5/2

Find the zeros of 6x^2+19x+4=2x-1

The zeros of 6x^2+19x+4=2x-1 are x=-1/3 ,x=-5/2

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6 x^{2} + 19 x + 4 = 2 x - 1

x = - \frac{1}{3}, x = - \frac{5}{2}

Decimal Notation

x = - 0.33333 \dots, x = - 2.5

Solution steps

6 x^{2} + 19 x + 4 = 2 x - 1

Move

1

to the left side

6 x^{2} + 19 x + 5 = 2 x

Move

2 x

to the left side

6 x^{2} + 17 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 \cdot 5 = 13

x_{1, 2} = \frac{- 17 \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 17 + 13}{2 \cdot 6}, x_{2} = \frac{- 17 - 13}{2 \cdot 6}

x = \frac{- 17 + 13}{2 \cdot 6} : - \frac{1}{3}

x = \frac{- 17 - 13}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{5}{2}

x, x^{2} - 8 x = 0

2 x^{2} + 8 x + 14 = 0

(x) = x^{2} + x - 6

x^{2} + 3 x + 2 = x + 2

- 2 x^{2} + 12 x - 13 = 0

What are the solutions to the equation 6x^2+19x+4=2x-1 ?
The solutions to the equation 6x^2+19x+4=2x-1 are x=-1/3 ,x=-5/2
Find the zeros of 6x^2+19x+4=2x-1
The zeros of 6x^2+19x+4=2x-1 are x=-1/3 ,x=-5/2