What are the solutions to the equation 6x^2-6x+2=0 ?

The solutions to the equation 6x^2-6x+2=0 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6

Find the zeros of 6x^2-6x+2=0

The zeros of 6x^2-6x+2=0 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6

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6 x^{2} - 6 x + 2 = 0

x = \frac{1}{2} + i \frac{3}{6}, x = \frac{1}{2} - i \frac{3}{6}

Solution steps

6 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

Simplify

(- 6)^{2} - 4 \cdot 6 \cdot 2 : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 6}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 6}

x = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 6} : \frac{1}{2} + i \frac{3}{6}

x = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 6} : \frac{1}{2} - i \frac{3}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{6}, x = \frac{1}{2} - i \frac{3}{6}

6 y^{2} + 5 y - 4 = 0

25 t^{2} - 10 t + 1 = 0

x^{2} - 18 x - 19 = 0

x^{2} = - 2 (2 x + 1)

x^{2} - \frac{3}{4} x = - \frac{1}{4}

What are the solutions to the equation 6x^2-6x+2=0 ?
The solutions to the equation 6x^2-6x+2=0 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6
Find the zeros of 6x^2-6x+2=0
The zeros of 6x^2-6x+2=0 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6