What are the solutions to the equation 6y^2+5y-4=0 ?

The solutions to the equation 6y^2+5y-4=0 are y= 1/2 ,y=-4/3

Find the zeros of 6y^2+5y-4=0

The zeros of 6y^2+5y-4=0 are y= 1/2 ,y=-4/3

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6 y^{2} + 5 y - 4 = 0

y = \frac{1}{2}, y = - \frac{4}{3}

Decimal Notation

y = 0.5, y = - 1.33333 \dots

Solution steps

6 y^{2} + 5 y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 4) = 11

y_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- 5 + 11}{2 \cdot 6}, y_{2} = \frac{- 5 - 11}{2 \cdot 6}

y = \frac{- 5 + 11}{2 \cdot 6} : \frac{1}{2}

y = \frac{- 5 - 11}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = - \frac{4}{3}

25 t^{2} - 10 t + 1 = 0

x^{2} - 18 x - 19 = 0

x^{2} = - 2 (2 x + 1)

x^{2} - \frac{3}{4} x = - \frac{1}{4}

8 t^{2} - 64 t + 281 = 0

What are the solutions to the equation 6y^2+5y-4=0 ?
The solutions to the equation 6y^2+5y-4=0 are y= 1/2 ,y=-4/3
Find the zeros of 6y^2+5y-4=0
The zeros of 6y^2+5y-4=0 are y= 1/2 ,y=-4/3