What are the solutions to the equation 5-3x^2=7 ?

The solutions to the equation 5-3x^2=7 are x=sqrt(2/3)i,x=-sqrt(2/3)i

Find the zeros of 5-3x^2=7

The zeros of 5-3x^2=7 are x=sqrt(2/3)i,x=-sqrt(2/3)i

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5 - 3 x^{2} = 7

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

5 - 3 x^{2} = 7

Move

5

to the right side

- 3 x^{2} = 2

Divide both sides by

- 3

x^{2} = - \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{3}, x = - - \frac{2}{3}

- \frac{2}{3} = \frac{2}{3} i

- - \frac{2}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

16 x^{2} + 82 x - 6 = 0

4 x^{2} + 3 x - 9 = 0

x, w = (x - 1) (x + 5)

x, (x - 1)^{2} + y^{2} = 0

5 x^{2} - 20 x + 6 = 0

What are the solutions to the equation 5-3x^2=7 ?
The solutions to the equation 5-3x^2=7 are x=sqrt(2/3)i,x=-sqrt(2/3)i
Find the zeros of 5-3x^2=7
The zeros of 5-3x^2=7 are x=sqrt(2/3)i,x=-sqrt(2/3)i