What are the solutions to the equation 16x^2+8sqrt(2)x-6=0 ?

The solutions to the equation 16x^2+8sqrt(2)x-6=0 are x= 1/(2sqrt(2)),x=-3/(2sqrt(2))

Find the zeros of 16x^2+8sqrt(2)x-6=0

The zeros of 16x^2+8sqrt(2)x-6=0 are x= 1/(2sqrt(2)),x=-3/(2sqrt(2))

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16 x^{2} + 82 x - 6 = 0

x = \frac{1}{2 2}, x = - \frac{3}{2 2}

Decimal Notation

x = 0.35355 \dots, x = - 1.06066 \dots

Solution steps

16 x^{2} + 82 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 2 \pm ( 8 2 ) ^{2} - 4 \cdot 16 ( - 6 )}{2 \cdot 16}

(82)^{2} - 4 \cdot 16 (- 6) = 162

x_{1, 2} = \frac{- 8 2 \pm 16 2}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 8 2 + 16 2}{2 \cdot 16}, x_{2} = \frac{- 8 2 - 16 2}{2 \cdot 16}

x = \frac{- 8 2 + 16 2}{2 \cdot 16} : \frac{1}{2 2}

x = \frac{- 8 2 - 16 2}{2 \cdot 16} : - \frac{3}{2 2}

The solutions to the quadratic equation are:

x = \frac{1}{2 2}, x = - \frac{3}{2 2}

4 x^{2} + 3 x - 9 = 0

x, w = (x - 1) (x + 5)

x, (x - 1)^{2} + y^{2} = 0

5 x^{2} - 20 x + 6 = 0

x^{2} - x - 49 = 0

What are the solutions to the equation 16x^2+8sqrt(2)x-6=0 ?
The solutions to the equation 16x^2+8sqrt(2)x-6=0 are x= 1/(2sqrt(2)),x=-3/(2sqrt(2))
Find the zeros of 16x^2+8sqrt(2)x-6=0
The zeros of 16x^2+8sqrt(2)x-6=0 are x= 1/(2sqrt(2)),x=-3/(2sqrt(2))