What are the solutions to the equation z^2-6z+10=0 ?

The solutions to the equation z^2-6z+10=0 are z=3+i,z=3-i

Find the zeros of z^2-6z+10=0

The zeros of z^2-6z+10=0 are z=3+i,z=3-i

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z^{2} - 6 z + 10 = 0

z = 3 + i, z = 3 - i

Solution steps

z^{2} - 6 z + 10 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 10 : 2 i

z_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 1}, z_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 1}

z = \frac{- ( - 6 ) + 2 i}{2 \cdot 1} : 3 + i

z = \frac{- ( - 6 ) - 2 i}{2 \cdot 1} : 3 - i

The solutions to the quadratic equation are:

z = 3 + i, z = 3 - i

x^{2} - 16 = 2 x - 1

- x^{2} + 3 x

- 3 x^{2} + 12 x + 15 = 0

n^{2} - 6 n + 9 = 0

450 - 5 t - 4.9 t^{2} = 0

What are the solutions to the equation z^2-6z+10=0 ?
The solutions to the equation z^2-6z+10=0 are z=3+i,z=3-i
Find the zeros of z^2-6z+10=0
The zeros of z^2-6z+10=0 are z=3+i,z=3-i