What are the solutions to the equation 450-5t-4.9t^2=0 ?

The solutions to the equation 450-5t-4.9t^2=0 are t=-(5(5+sqrt(8845)))/(49),t=(5(sqrt(8845)-5))/(49)

Find the zeros of 450-5t-4.9t^2=0

The zeros of 450-5t-4.9t^2=0 are t=-(5(5+sqrt(8845)))/(49),t=(5(sqrt(8845)-5))/(49)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

450 - 5 t - 4.9 t^{2} = 0

t = - \frac{5 ( 5 + 8845 )}{49}, t = \frac{5 ( 8845 - 5 )}{49}

Decimal Notation

t = - 10.10692 \dots, t = 9.08651 \dots

Solution steps

450 - 5 t - 4.9 t^{2} = 0

Multiply both sides by

10

4500 - 50 t - 49 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 t^{2} - 50 t + 4500 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 ( - 49 ) \cdot 4500}{2 ( - 49 )}

(- 50)^{2} - 4 (- 49) \cdot 4500 = 108845

t_{1, 2} = \frac{- ( - 50 ) \pm 10 8845}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- ( - 50 ) + 10 8845}{2 ( - 49 )}, t_{2} = \frac{- ( - 50 ) - 10 8845}{2 ( - 49 )}

t = \frac{- ( - 50 ) + 10 8845}{2 ( - 49 )} : - \frac{5 ( 5 + 8845 )}{49}

t = \frac{- ( - 50 ) - 10 8845}{2 ( - 49 )} : \frac{5 ( 8845 - 5 )}{49}

The solutions to the quadratic equation are:

t = - \frac{5 ( 5 + 8845 )}{49}, t = \frac{5 ( 8845 - 5 )}{49}

x^{2} + \frac{6}{7} x - 1 = 0

- x^{2} - 4 = 14

2 b^{2} = 32

3 x^{2} + 1 x = 0

x^{2} + 5 x - 6 = 0

What are the solutions to the equation 450-5t-4.9t^2=0 ?
The solutions to the equation 450-5t-4.9t^2=0 are t=-(5(5+sqrt(8845)))/(49),t=(5(sqrt(8845)-5))/(49)
Find the zeros of 450-5t-4.9t^2=0
The zeros of 450-5t-4.9t^2=0 are t=-(5(5+sqrt(8845)))/(49),t=(5(sqrt(8845)-5))/(49)