What are the solutions to the equation -3x^2+12x+15=0 ?

The solutions to the equation -3x^2+12x+15=0 are x=-1,x=5

Find the zeros of -3x^2+12x+15=0

The zeros of -3x^2+12x+15=0 are x=-1,x=5

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- 3 x^{2} + 12 x + 15 = 0

x = - 1, x = 5

Solution steps

- 3 x^{2} + 12 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) \cdot 15}{2 ( - 3 )}

1 2^{2} - 4 (- 3) \cdot 15 = 18

x_{1, 2} = \frac{- 12 \pm 18}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 18}{2 ( - 3 )}, x_{2} = \frac{- 12 - 18}{2 ( - 3 )}

x = \frac{- 12 + 18}{2 ( - 3 )} : - 1

x = \frac{- 12 - 18}{2 ( - 3 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

n^{2} - 6 n + 9 = 0

450 - 5 t - 4.9 t^{2} = 0

x^{2} + \frac{6}{7} x - 1 = 0

- x^{2} - 4 = 14

2 b^{2} = 32

What are the solutions to the equation -3x^2+12x+15=0 ?
The solutions to the equation -3x^2+12x+15=0 are x=-1,x=5
Find the zeros of -3x^2+12x+15=0
The zeros of -3x^2+12x+15=0 are x=-1,x=5