What are the solutions to the equation x^2+6/7 x-1=0 ?

The solutions to the equation x^2+6/7 x-1=0 are x=(-3+sqrt(58))/7 ,x=-(3+sqrt(58))/7

Find the zeros of x^2+6/7 x-1=0

The zeros of x^2+6/7 x-1=0 are x=(-3+sqrt(58))/7 ,x=-(3+sqrt(58))/7

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x^{2} + \frac{6}{7} x - 1 = 0

x = \frac{- 3 + 58}{7}, x = - \frac{3 + 58}{7}

Decimal Notation

x = 0.65939 \dots, x = - 1.51653 \dots

Solution steps

x^{2} + \frac{6}{7} x - 1 = 0

Multiply both sides by

7

7 x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 7 ( - 7 )}{2 \cdot 7}

6^{2} - 4 \cdot 7 (- 7) = 258

x_{1, 2} = \frac{- 6 \pm 2 58}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 6 + 2 58}{2 \cdot 7}, x_{2} = \frac{- 6 - 2 58}{2 \cdot 7}

x = \frac{- 6 + 2 58}{2 \cdot 7} : \frac{- 3 + 58}{7}

x = \frac{- 6 - 2 58}{2 \cdot 7} : - \frac{3 + 58}{7}

The solutions to the quadratic equation are:

x = \frac{- 3 + 58}{7}, x = - \frac{3 + 58}{7}

- x^{2} - 4 = 14

2 b^{2} = 32

3 x^{2} + 1 x = 0

x^{2} + 5 x - 6 = 0

2^{2} + b^{2} = 1 1^{2}

What are the solutions to the equation x^2+6/7 x-1=0 ?
The solutions to the equation x^2+6/7 x-1=0 are x=(-3+sqrt(58))/7 ,x=-(3+sqrt(58))/7
Find the zeros of x^2+6/7 x-1=0
The zeros of x^2+6/7 x-1=0 are x=(-3+sqrt(58))/7 ,x=-(3+sqrt(58))/7