What are the solutions to the equation h^2=13^2+16^2 ?

The solutions to the equation h^2=13^2+16^2 are h=5sqrt(17),h=-5sqrt(17)

Find the zeros of h^2=13^2+16^2

The zeros of h^2=13^2+16^2 are h=5sqrt(17),h=-5sqrt(17)

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h^{2} = 1 3^{2} + 1 6^{2}

h = 517, h = - 517

Decimal Notation

h = 20.61552 \dots, h = - 20.61552 \dots

Solution steps

h^{2} = 1 3^{2} + 1 6^{2}

Simplify

1 3^{2} + 1 6^{2} : 425

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

h = 425, h = - 425

425 = 517

- 425 = - 517

h = 517, h = - 517

\frac{5}{3} x^{2} - x = \frac{1}{3}

x^{2} - 4 x - 25 = 0

- x^{2} - 13 x - 18 = - 3 x

\frac{41}{144} x^{2} + 1 = \frac{60}{7} x - \frac{444}{7}

x^{2} + 3 x - 1 = 0

What are the solutions to the equation h^2=13^2+16^2 ?
The solutions to the equation h^2=13^2+16^2 are h=5sqrt(17),h=-5sqrt(17)
Find the zeros of h^2=13^2+16^2
The zeros of h^2=13^2+16^2 are h=5sqrt(17),h=-5sqrt(17)