What are the solutions to the equation x^2-4x-25=0 ?

The solutions to the equation x^2-4x-25=0 are x=2+sqrt(29),x=2-sqrt(29)

Find the zeros of x^2-4x-25=0

The zeros of x^2-4x-25=0 are x=2+sqrt(29),x=2-sqrt(29)

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x^{2} - 4 x - 25 = 0

x = 2 + 29, x = 2 - 29

Decimal Notation

x = 7.38516 \dots, x = - 3.38516 \dots

Solution steps

x^{2} - 4 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 25) = 229

x_{1, 2} = \frac{- ( - 4 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 29}{2 \cdot 1} : 2 + 29

x = \frac{- ( - 4 ) - 2 29}{2 \cdot 1} : 2 - 29

The solutions to the quadratic equation are:

x = 2 + 29, x = 2 - 29

- x^{2} - 13 x - 18 = - 3 x

\frac{41}{144} x^{2} + 1 = \frac{60}{7} x - \frac{444}{7}

x^{2} + 3 x - 1 = 0

s^{2} + 18 s + 81 = 0

2 (x^{2} + 4 x + 4) + 1 = 51

What are the solutions to the equation x^2-4x-25=0 ?
The solutions to the equation x^2-4x-25=0 are x=2+sqrt(29),x=2-sqrt(29)
Find the zeros of x^2-4x-25=0
The zeros of x^2-4x-25=0 are x=2+sqrt(29),x=2-sqrt(29)