What are the solutions to the equation -x^2-13x-18=-3x ?

The solutions to the equation -x^2-13x-18=-3x are x=-5-sqrt(7),x=-5+sqrt(7)

Find the zeros of -x^2-13x-18=-3x

The zeros of -x^2-13x-18=-3x are x=-5-sqrt(7),x=-5+sqrt(7)

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- x^{2} - 13 x - 18 = - 3 x

x = - 5 - 7, x = - 5 + 7

Decimal Notation

x = - 7.64575 \dots, x = - 2.35424 \dots

Solution steps

- x^{2} - 13 x - 18 = - 3 x

Move

3 x

to the left side

- x^{2} - 10 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) (- 18) = 27

x_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 7}{2 ( - 1 )}, x_{2} = \frac{- ( - 10 ) - 2 7}{2 ( - 1 )}

x = \frac{- ( - 10 ) + 2 7}{2 ( - 1 )} : - 5 - 7

x = \frac{- ( - 10 ) - 2 7}{2 ( - 1 )} : - 5 + 7

The solutions to the quadratic equation are:

x = - 5 - 7, x = - 5 + 7

\frac{41}{144} x^{2} + 1 = \frac{60}{7} x - \frac{444}{7}

x^{2} + 3 x - 1 = 0

s^{2} + 18 s + 81 = 0

2 (x^{2} + 4 x + 4) + 1 = 51

- 6 x^{2} + 12 x - 6 = 0

What are the solutions to the equation -x^2-13x-18=-3x ?
The solutions to the equation -x^2-13x-18=-3x are x=-5-sqrt(7),x=-5+sqrt(7)
Find the zeros of -x^2-13x-18=-3x
The zeros of -x^2-13x-18=-3x are x=-5-sqrt(7),x=-5+sqrt(7)