What are the solutions to the equation s^2+18s+81=0 ?

The solutions to the equation s^2+18s+81=0 are s=-9

Find the zeros of s^2+18s+81=0

The zeros of s^2+18s+81=0 are s=-9

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s^{2} + 18 s + 81 = 0

s = - 9

Solution steps

s^{2} + 18 s + 81 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

s_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

s = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

s = - 9

The solution to the quadratic equation is:

s = - 9

2 (x^{2} + 4 x + 4) + 1 = 51

- 6 x^{2} + 12 x - 6 = 0

n (n + 14) = - 4

4 x^{2} - 28 x = - 49

- x^{2} - 4 x + 32 = 0

What are the solutions to the equation s^2+18s+81=0 ?
The solutions to the equation s^2+18s+81=0 are s=-9
Find the zeros of s^2+18s+81=0
The zeros of s^2+18s+81=0 are s=-9