What are the solutions to the equation -6x^2+12x-6=0 ?

The solutions to the equation -6x^2+12x-6=0 are x=1

Find the zeros of -6x^2+12x-6=0

The zeros of -6x^2+12x-6=0 are x=1

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- 6 x^{2} + 12 x - 6 = 0

x = 1

Solution steps

- 6 x^{2} + 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 6 ) ( - 6 )}{2 ( - 6 )}

1 2^{2} - 4 (- 6) (- 6) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 6 )}

x = \frac{- 12}{2 ( - 6 )}

\frac{- 12}{2 ( - 6 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

n (n + 14) = - 4

4 x^{2} - 28 x = - 49

- x^{2} - 4 x + 32 = 0

12 a^{2} - 7 a = 12

4 x^{2} + 64 x = 0

What are the solutions to the equation -6x^2+12x-6=0 ?
The solutions to the equation -6x^2+12x-6=0 are x=1
Find the zeros of -6x^2+12x-6=0
The zeros of -6x^2+12x-6=0 are x=1