What are the solutions to the equation 4x^2-28x=-49 ?

The solutions to the equation 4x^2-28x=-49 are x= 7/2

Find the zeros of 4x^2-28x=-49

The zeros of 4x^2-28x=-49 are x= 7/2

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4 x^{2} - 28 x = - 49

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

4 x^{2} - 28 x = - 49

Move

49

to the left side

4 x^{2} - 28 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 49}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 28 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 28 )}{2 \cdot 4}

\frac{- ( - 28 )}{2 \cdot 4} = \frac{7}{2}

x = \frac{7}{2}

The solution to the quadratic equation is:

x = \frac{7}{2}

- x^{2} - 4 x + 32 = 0

12 a^{2} - 7 a = 12

4 x^{2} + 64 x = 0

36 s^{2} - 12 s + 1 = 0

4 = - 16 t^{2} + 32 t + 6

What are the solutions to the equation 4x^2-28x=-49 ?
The solutions to the equation 4x^2-28x=-49 are x= 7/2
Find the zeros of 4x^2-28x=-49
The zeros of 4x^2-28x=-49 are x= 7/2