What are the solutions to the equation 7x^2-12x=36+7x ?

The solutions to the equation 7x^2-12x=36+7x are x=4,x=-9/7

Find the zeros of 7x^2-12x=36+7x

The zeros of 7x^2-12x=36+7x are x=4,x=-9/7

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7 x^{2} - 12 x = 36 + 7 x

x = 4, x = - \frac{9}{7}

Decimal Notation

x = 4, x = - 1.28571 \dots

Solution steps

7 x^{2} - 12 x = 36 + 7 x

Move

7 x

to the left side

7 x^{2} - 19 x = 36

Move

36

to the left side

7 x^{2} - 19 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 7 ( - 36 )}{2 \cdot 7}

(- 19)^{2} - 4 \cdot 7 (- 36) = 37

x_{1, 2} = \frac{- ( - 19 ) \pm 37}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 37}{2 \cdot 7}, x_{2} = \frac{- ( - 19 ) - 37}{2 \cdot 7}

x = \frac{- ( - 19 ) + 37}{2 \cdot 7} : 4

x = \frac{- ( - 19 ) - 37}{2 \cdot 7} : - \frac{9}{7}

The solutions to the quadratic equation are:

x = 4, x = - \frac{9}{7}

6 a^{2} + 10 = 60 + 4 a^{2}

x^{2} + 2 x - 15 = 0

(s + 4)^{2} = 0

(x - 4)^{2} + (x - 3)^{2} = 25

V = \frac{0.005}{2} (1000) (6.5 - V - 0.5)^{2}

What are the solutions to the equation 7x^2-12x=36+7x ?
The solutions to the equation 7x^2-12x=36+7x are x=4,x=-9/7
Find the zeros of 7x^2-12x=36+7x
The zeros of 7x^2-12x=36+7x are x=4,x=-9/7