What are the solutions to the equation completesquare x^2-12+26=0 ?

The solutions to the equation completesquare x^2-12+26=0 are x=sqrt(14)i,x=-sqrt(14)i

Find the zeros of completesquare x^2-12+26=0

The zeros of completesquare x^2-12+26=0 are x=sqrt(14)i,x=-sqrt(14)i

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x^{2} - 12 + 26 = 0

x = 14 i, x = - 14 i

Solution steps

x^{2} - 12 + 26 = 0

Move

12

to the right side

x^{2} + 26 = 12

Move

26

to the right side

x^{2} = - 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 14, x = - - 14

- 14 = 14 i

- - 14 = - 14 i

x = 14 i, x = - 14 i

2 a^{2} - 8 a = 0

- x^{2} - 2 - x = - 4 - 2 x^{2} + 5 x

2 5^{2} = x^{2} + 7^{2}

3 x^{2} - 5 x = 4 - 3 x^{2}

72 x^{2} = 8 x

What are the solutions to the equation completesquare x^2-12+26=0 ?
The solutions to the equation completesquare x^2-12+26=0 are x=sqrt(14)i,x=-sqrt(14)i
Find the zeros of completesquare x^2-12+26=0
The zeros of completesquare x^2-12+26=0 are x=sqrt(14)i,x=-sqrt(14)i