What are the solutions to the equation -6x^2+6x-1=0 ?

The solutions to the equation -6x^2+6x-1=0 are x=(3-sqrt(3))/6 ,x=(3+sqrt(3))/6

Find the zeros of -6x^2+6x-1=0

The zeros of -6x^2+6x-1=0 are x=(3-sqrt(3))/6 ,x=(3+sqrt(3))/6

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- 6 x^{2} + 6 x - 1 = 0

x = \frac{3 - 3}{6}, x = \frac{3 + 3}{6}

Decimal Notation

x = 0.21132 \dots, x = 0.78867 \dots

Solution steps

- 6 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 6 ) ( - 1 )}{2 ( - 6 )}

6^{2} - 4 (- 6) (- 1) = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 ( - 6 )}, x_{2} = \frac{- 6 - 2 3}{2 ( - 6 )}

x = \frac{- 6 + 2 3}{2 ( - 6 )} : \frac{3 - 3}{6}

x = \frac{- 6 - 2 3}{2 ( - 6 )} : \frac{3 + 3}{6}

The solutions to the quadratic equation are:

x = \frac{3 - 3}{6}, x = \frac{3 + 3}{6}

7^{2} + b^{2} = 1 5^{2}

36 x^{2} + 96 x + 48 = 0

12 x^{2} + 14 x - 6 = 0

- y^{2} + 6 y

x, y^{3} x + y^{2} x^{2} = 6

What are the solutions to the equation -6x^2+6x-1=0 ?
The solutions to the equation -6x^2+6x-1=0 are x=(3-sqrt(3))/6 ,x=(3+sqrt(3))/6
Find the zeros of -6x^2+6x-1=0
The zeros of -6x^2+6x-1=0 are x=(3-sqrt(3))/6 ,x=(3+sqrt(3))/6