What are the solutions to the equation (x+4)^2=15 ?

The solutions to the equation (x+4)^2=15 are x=sqrt(15)-4,x=-sqrt(15)-4

Find the zeros of (x+4)^2=15

The zeros of (x+4)^2=15 are x=sqrt(15)-4,x=-sqrt(15)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 4)^{2} = 15

x = 15 - 4, x = - 15 - 4

Decimal Notation

x = - 0.12701 \dots, x = - 7.87298 \dots

Solution steps

(x + 4)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 15 : x = 15 - 4

Solve

x + 4 = - 15 : x = - 15 - 4

The solutions to the quadratic equation are:

x = 15 - 4, x = - 15 - 4

6 - 20 x + 12 x^{2} = 0

5 x^{2} + x - 5 = 0

5 y^{2} = 100

4 y^{2} + 60 = 100

3 x^{2} + 2 x + 12 = - 13 x

What are the solutions to the equation (x+4)^2=15 ?
The solutions to the equation (x+4)^2=15 are x=sqrt(15)-4,x=-sqrt(15)-4
Find the zeros of (x+4)^2=15
The zeros of (x+4)^2=15 are x=sqrt(15)-4,x=-sqrt(15)-4