What are the solutions to the equation 6-20x+12x^2=0 ?

The solutions to the equation 6-20x+12x^2=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6

Find the zeros of 6-20x+12x^2=0

The zeros of 6-20x+12x^2=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6

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6 - 20 x + 12 x^{2} = 0

x = \frac{5 + 7}{6}, x = \frac{5 - 7}{6}

Decimal Notation

x = 1.27429 \dots, x = 0.39237 \dots

Solution steps

6 - 20 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 20 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 12 \cdot 6}{2 \cdot 12}

(- 20)^{2} - 4 \cdot 12 \cdot 6 = 47

x_{1, 2} = \frac{- ( - 20 ) \pm 4 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 7}{2 \cdot 12}, x_{2} = \frac{- ( - 20 ) - 4 7}{2 \cdot 12}

x = \frac{- ( - 20 ) + 4 7}{2 \cdot 12} : \frac{5 + 7}{6}

x = \frac{- ( - 20 ) - 4 7}{2 \cdot 12} : \frac{5 - 7}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 7}{6}, x = \frac{5 - 7}{6}

5 x^{2} + x - 5 = 0

5 y^{2} = 100

4 y^{2} + 60 = 100

3 x^{2} + 2 x + 12 = - 13 x

6 x^{2} - 6 x - 5 = 0

What are the solutions to the equation 6-20x+12x^2=0 ?
The solutions to the equation 6-20x+12x^2=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6
Find the zeros of 6-20x+12x^2=0
The zeros of 6-20x+12x^2=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6