What are the solutions to the equation y^2-8y-16=0 ?

The solutions to the equation y^2-8y-16=0 are y=4(1+sqrt(2)),y=4(1-sqrt(2))

Find the zeros of y^2-8y-16=0

The zeros of y^2-8y-16=0 are y=4(1+sqrt(2)),y=4(1-sqrt(2))

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y^{2} - 8 y - 16 = 0

y = 4 (1 + 2), y = 4 (1 - 2)

Decimal Notation

y = 9.65685 \dots, y = - 1.65685 \dots

Solution steps

y^{2} - 8 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 16) = 82

y_{1, 2} = \frac{- ( - 8 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 8 2}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 8 2}{2 \cdot 1}

y = \frac{- ( - 8 ) + 8 2}{2 \cdot 1} : 4 (1 + 2)

y = \frac{- ( - 8 ) - 8 2}{2 \cdot 1} : 4 (1 - 2)

The solutions to the quadratic equation are:

y = 4 (1 + 2), y = 4 (1 - 2)

x^{2} - 6 x + 7 = 0

x^{2} - 8 x = 12

- 2 x^{2} + 2 x + 7 = 0

x (x + 2) = e^{4}

(5 x - 1) (x + 1) = 0

What are the solutions to the equation y^2-8y-16=0 ?
The solutions to the equation y^2-8y-16=0 are y=4(1+sqrt(2)),y=4(1-sqrt(2))
Find the zeros of y^2-8y-16=0
The zeros of y^2-8y-16=0 are y=4(1+sqrt(2)),y=4(1-sqrt(2))