What are the solutions to the equation 4b^2+2b-2=0 ?

The solutions to the equation 4b^2+2b-2=0 are b= 1/2 ,b=-1

Find the zeros of 4b^2+2b-2=0

The zeros of 4b^2+2b-2=0 are b= 1/2 ,b=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 b^{2} + 2 b - 2 = 0

b = \frac{1}{2}, b = - 1

Decimal Notation

b = 0.5, b = - 1

Solution steps

4 b^{2} + 2 b - 2 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 2) = 6

b_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- 2 + 6}{2 \cdot 4}, b_{2} = \frac{- 2 - 6}{2 \cdot 4}

b = \frac{- 2 + 6}{2 \cdot 4} : \frac{1}{2}

b = \frac{- 2 - 6}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

b = \frac{1}{2}, b = - 1

10 x^{2} - 12 x = 0

25 x^{2} + 100 x + 100 = 0

x^{2} - 65 x + 950 = 0

2 x^{1} + 8 x^{2} = 10

x^{2} + 9 x + 25 = 0

What are the solutions to the equation 4b^2+2b-2=0 ?
The solutions to the equation 4b^2+2b-2=0 are b= 1/2 ,b=-1
Find the zeros of 4b^2+2b-2=0
The zeros of 4b^2+2b-2=0 are b= 1/2 ,b=-1