What are the solutions to the equation 4x^2-5=31 ?

The solutions to the equation 4x^2-5=31 are x=3,x=-3

Find the zeros of 4x^2-5=31

The zeros of 4x^2-5=31 are x=3,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 5 = 31

x = 3, x = - 3

Solution steps

4 x^{2} - 5 = 31

Move

5

to the right side

4 x^{2} = 36

Divide both sides by

4

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

n^{2} - 18 n = - 73

x^{2} - 10 x - 13 = 0

- 3 x^{2} + 11 x + 9 = 1

5.56 \cdot 1 0^{- 10} = \frac{x ^{2}}{2.5}

x^{2} - 1 = - 2 x

What are the solutions to the equation 4x^2-5=31 ?
The solutions to the equation 4x^2-5=31 are x=3,x=-3
Find the zeros of 4x^2-5=31
The zeros of 4x^2-5=31 are x=3,x=-3