What are the solutions to the equation -1(x-2)^2-1=0 ?

The solutions to the equation -1(x-2)^2-1=0 are x=i+2,x=-i+2

Find the zeros of -1(x-2)^2-1=0

The zeros of -1(x-2)^2-1=0 are x=i+2,x=-i+2

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- 1 (x - 2)^{2} - 1 = 0

x = i + 2, x = - i + 2

Solution steps

- 1 \cdot (x - 2)^{2} - 1 = 0

Move

1

to the right side

- 1 \cdot (x - 2)^{2} = 1

Divide both sides by

- 1

(x - 2)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 1 : x = i + 2

Solve

x - 2 = - - 1 : x = - i + 2

The solutions to the quadratic equation are:

x = i + 2, x = - i + 2

12 x^{2} - 68 x + 72 = 0

12 x^{2} - 104 x + 168 = 0

- 36 x^{2} = 0

p^{2} = 40

- 5 x^{2} + 7 x + 9 = 0

What are the solutions to the equation -1(x-2)^2-1=0 ?
The solutions to the equation -1(x-2)^2-1=0 are x=i+2,x=-i+2
Find the zeros of -1(x-2)^2-1=0
The zeros of -1(x-2)^2-1=0 are x=i+2,x=-i+2