What are the solutions to the equation (x^2)/4-x-3=0 ?

The solutions to the equation (x^2)/4-x-3=0 are x=6,x=-2

Find the zeros of (x^2)/4-x-3=0

The zeros of (x^2)/4-x-3=0 are x=6,x=-2

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\frac{x ^{2}}{4} - x - 3 = 0

x = 6, x = - 2

Solution steps

\frac{x ^{2}}{4} - x - 3 = 0

Multiply both sides by

4

x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

(x + 4) (x - 9) + 5 x = 0

4 r^{2} - r = 5

5 x^{2} + 12 x - 4 = 0

- 4 x^{2} - 48 x - 208 = 0

x^{2} + 10 = 6 x

What are the solutions to the equation (x^2)/4-x-3=0 ?
The solutions to the equation (x^2)/4-x-3=0 are x=6,x=-2
Find the zeros of (x^2)/4-x-3=0
The zeros of (x^2)/4-x-3=0 are x=6,x=-2