What are the solutions to the equation (x+4)(x-9)+5x=0 ?

The solutions to the equation (x+4)(x-9)+5x=0 are x=6,x=-6

Find the zeros of (x+4)(x-9)+5x=0

The zeros of (x+4)(x-9)+5x=0 are x=6,x=-6

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(x + 4) (x - 9) + 5 x = 0

x = 6, x = - 6

Solution steps

(x + 4) (x - 9) + 5 x = 0

Expand

(x + 4) (x - 9) + 5 x : x^{2} - 36

x^{2} - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 36) = 12

x_{1, 2} = \frac{- 0 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 12}{2 \cdot 1}, x_{2} = \frac{- 0 - 12}{2 \cdot 1}

x = \frac{- 0 + 12}{2 \cdot 1} : 6

x = \frac{- 0 - 12}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 6, x = - 6

4 r^{2} - r = 5

5 x^{2} + 12 x - 4 = 0

- 4 x^{2} - 48 x - 208 = 0

x^{2} + 10 = 6 x

x^{2} + 10 = 25

What are the solutions to the equation (x+4)(x-9)+5x=0 ?
The solutions to the equation (x+4)(x-9)+5x=0 are x=6,x=-6
Find the zeros of (x+4)(x-9)+5x=0
The zeros of (x+4)(x-9)+5x=0 are x=6,x=-6