What are the solutions to the equation x^2+10=6x ?

The solutions to the equation x^2+10=6x are x=3+i,x=3-i

Find the zeros of x^2+10=6x

The zeros of x^2+10=6x are x=3+i,x=3-i

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x^{2} + 10 = 6 x

x = 3 + i, x = 3 - i

Solution steps

x^{2} + 10 = 6 x

Move

6 x

to the left side

x^{2} + 10 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 10 : 2 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 i}{2 \cdot 1} : 3 + i

x = \frac{- ( - 6 ) - 2 i}{2 \cdot 1} : 3 - i

The solutions to the quadratic equation are:

x = 3 + i, x = 3 - i

x^{2} + 10 = 25

x, x^{2} + (\frac{4 x}{3})^{2} = 225

0 = x^{2} - 12 x

1 3^{2} + 1 2^{2} = c^{2}

(3 x + 1) (x - 4) = (2 x + 1) (x - 1) - 37

What are the solutions to the equation x^2+10=6x ?
The solutions to the equation x^2+10=6x are x=3+i,x=3-i
Find the zeros of x^2+10=6x
The zeros of x^2+10=6x are x=3+i,x=3-i